(w^2-2w+1)+(2w-5+w^2)=

Solution for (w^2-2w+1)+(2w-5+w^2)= equation:

Simplifying
(w2 + -2w + 1) + (2w + -5 + w2) = 0

Reorder the terms:
(1 + -2w + w2) + (2w + -5 + w2) = 0

Remove parenthesis around (1 + -2w + w2)
1 + -2w + w2 + (2w + -5 + w2) = 0

Reorder the terms:
1 + -2w + w2 + (-5 + 2w + w2) = 0

Remove parenthesis around (-5 + 2w + w2)
1 + -2w + w2 + -5 + 2w + w2 = 0

Reorder the terms:
1 + -5 + -2w + 2w + w2 + w2 = 0

Combine like terms: 1 + -5 = -4
-4 + -2w + 2w + w2 + w2 = 0

Combine like terms: -2w + 2w = 0
-4 + 0 + w2 + w2 = 0
-4 + w2 + w2 = 0

Combine like terms: w2 + w2 = 2w2
-4 + 2w2 = 0

Solving
-4 + 2w2 = 0

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 2w2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 2w2 = 0 + 4
2w2 = 0 + 4

Combine like terms: 0 + 4 = 4
2w2 = 4

Divide each side by '2'.
w2 = 2

Simplifying
w2 = 2

Take the square root of each side:
w = {-1.414213562, 1.414213562}